Collision Response Question
here's a quicker way:
newDirectionOfBall = (2 * angleOfCollision) + 180Ëš  directionOfBall
where angleOfCollision is the angle which describes the point where the ball hit the circle
newDirectionOfBall = (2 * angleOfCollision) + 180Ëš  directionOfBall
where angleOfCollision is the angle which describes the point where the ball hit the circle
... I don't see how that's less complicated. I still would have to calculate all the angles, and then convert them back into vectors. I'm open to being convinced, though...
... And it gets even cooler!
Press return to spawn new balls. My machine can handle about 80 without dipping beneath 30FPS.
Now they bounce off of each other! Way cool!
Link: http://www.owlnet.rice.edu/~ajm4979/BG0.01.zip
Press return to spawn new balls. My machine can handle about 80 without dipping beneath 30FPS.
Now they bounce off of each other! Way cool!
Link: http://www.owlnet.rice.edu/~ajm4979/BG0.01.zip
blobbo Wrote:... I don't see how that's less complicated. I still would have to calculate all the angles, and then convert them back into vectors. I'm open to being convinced, though...
Don't your vectors already contain angles? For example, I'd probably make a C struct like this...
typedef struct Vector {
double angle;
double magnitude;
} Vector;
So where are these conversion calculations you're talking about?
hes probably using cartesian instead of polar coordinates, i.e. x and y instead of r and theta, so the conversion involes arc tangent from c>p and sine and cosine for p>c.
Sir, e^iÏ€ + 1 = 0, hence God exists; reply!
unknown is correct. My struct contains simply an x and a y coordinate which I normalise for calculations.
looks very cool, what kind of goal do you have in mind? take a look at this pinball game:http://www.secretlevel.de/RapidMotion.swf
also you might want to only bounce balls if their respective velocities are moving them closer together, it's a simple way of stopping them getting stuck together
also you might want to only bounce balls if their respective velocities are moving them closer together, it's a simple way of stopping them getting stuck together
I recommend you use bounding box collision before circle  circle detection to make it run faster, and also you need to do one of two things to avoid sticking,
either move the balls apart from eachother (ball A moves normalised direction from AB * disatnce/2 and B moves the negative of that) then decrease the velocity slightly to compensate, because you create and destroy energy by just moving objects which is unrealisttic,
or a much better way is to check if there is a collision, step back a frame and subdivide the time, basically play numguess until you get the balls almost perfectly touching each other instead of intersecting, then calculate their new velocites and animate by the rest of the time for that frame, and continue animating as usual afterwards.
actually I could write a tutorial on timestep subdivision, if that would be useful for people?
either move the balls apart from eachother (ball A moves normalised direction from AB * disatnce/2 and B moves the negative of that) then decrease the velocity slightly to compensate, because you create and destroy energy by just moving objects which is unrealisttic,
or a much better way is to check if there is a collision, step back a frame and subdivide the time, basically play numguess until you get the balls almost perfectly touching each other instead of intersecting, then calculate their new velocites and animate by the rest of the time for that frame, and continue animating as usual afterwards.
actually I could write a tutorial on timestep subdivision, if that would be useful for people?
Sir, e^iÏ€ + 1 = 0, hence God exists; reply!
unknown Wrote:I recommend you use bounding box collision before circle  circle detection to make it run fasterActually I believe sphere/circle collision detection is faster in general and definitely in this case.
Unknown:
 Bounding box will save processor cycles by avoiding sqrt, right? I think that's what you're saying
 Timestepping is the next implementation project I have. Would be nice to have some nice commented code to work from, but this is heavily documented already
Will: I've got a general idea in mind where 14 players each occupy a section of the circle's circumference. Each player has a "cannon" that can pitch back and forth, and fire balls into the circle. The idea is that you have to hit the other player's cannon. Think of it like reverse pong.
There's lots of ideas here, notably powerups and assorted obstacles. Ideally this is a multiplayer game, but networking scares the bejeezes out of me, so I'll program an AI first and maybe allow for two players on a single mac.
To avoid making a superAI, I think that I'd have some sort of "mission" mode where you have to collect objects in the ring while fighting away foes.
In the long, long, long range I see this being a really neat 3D game, with debris in the ring that the ball picks up, much like in Katamari. But the debris alters the balls trajectory, making it complicated.
I think it's a neat idea that shouldn't be too hard to implement. Might give me time to make a working game for once! That's why I'm using Quartz  I want to work comfortably in order to hopefully be able to finish this stupid project!
 Bounding box will save processor cycles by avoiding sqrt, right? I think that's what you're saying
 Timestepping is the next implementation project I have. Would be nice to have some nice commented code to work from, but this is heavily documented already
Will: I've got a general idea in mind where 14 players each occupy a section of the circle's circumference. Each player has a "cannon" that can pitch back and forth, and fire balls into the circle. The idea is that you have to hit the other player's cannon. Think of it like reverse pong.
There's lots of ideas here, notably powerups and assorted obstacles. Ideally this is a multiplayer game, but networking scares the bejeezes out of me, so I'll program an AI first and maybe allow for two players on a single mac.
To avoid making a superAI, I think that I'd have some sort of "mission" mode where you have to collect objects in the ring while fighting away foes.
In the long, long, long range I see this being a really neat 3D game, with debris in the ring that the ball picks up, much like in Katamari. But the debris alters the balls trajectory, making it complicated.
I think it's a neat idea that shouldn't be too hard to implement. Might give me time to make a working game for once! That's why I'm using Quartz  I want to work comfortably in order to hopefully be able to finish this stupid project!
sqrt(a) < sqrt(b) === a < b
dx = (a.xb.x)
dy = (a.yb.y)
if dx*dx+dy*dy < a.r*b.r
is slower than
if a.x+a.r > b.xb.r  if a.xa.r < b.x+b.r
if a.y+a.r > b.yb.r  if a.ya.r < b.y+b.r
dx = (a.xb.x)
dy = (a.yb.y)
if dx*dx+dy*dy < a.r*b.r
for lots of circles
There was a cool circular pong game called vortex or somthing I think, pre OS X.
dy = (a.yb.y)
if dx*dx+dy*dy < a.r*b.r
is slower than
if a.x+a.r > b.xb.r  if a.xa.r < b.x+b.r
if a.y+a.r > b.yb.r  if a.ya.r < b.y+b.r
dx = (a.xb.x)
dy = (a.yb.y)
if dx*dx+dy*dy < a.r*b.r
for lots of circles
There was a cool circular pong game called vortex or somthing I think, pre OS X.
Sir, e^iÏ€ + 1 = 0, hence God exists; reply!
Ok, so I've tried to implement timestepping by iterating back from my ball's current position to a point where it just is touching the surface of the collision object. Occasionally this doesn't work, however, and it causes these nasty hangs on occasion. I'm posting the full function for reference.
TIMESTEP_AMOUNT is currently defined as 0.1  I figured that was accurate enough.
Any ideas?
PHP Code:
 (void)collideBallWithOtherBalls:(BGBall *)ball
{
id collisionBall;
NSEnumerator *ballsEnumerator = [balls objectEnumerator];
while (collisionBall = [ballsEnumerator nextObject])
{
if (collisionBall != ball)
{
// Collision Detection
if (vectorDistance([collisionBall position], [ball position]) <
([collisionBall radius] + [ball radius]))
{
// COLLISION RESPONSE
/* Adjust position of balls to be in a pixelperfect collision, store the remainder
to be added afterwards */
float remainder = 0;
while (vectorDistance([collisionBall position], [ball position]) <
([collisionBall radius] + [ball radius]))
{
[collisionBall moveDistance:TIMESTEP_AMOUNT];
[ball moveDistance:TIMESTEP_AMOUNT];
remainder += TIMESTEP_AMOUNT;
}
vector normal = vectorNormalise(vectorSubtract([collisionBall position], [ball position]));
vector approachVel = vectorSubtract([ball direction], [collisionBall direction]);
float projectedApproachSpeed = vectorDotProduct(normal, approachVel);
vector velocityChange = vectorMultiply(normal, projectedApproachSpeed);
[collisionBall setDirection:vectorAdd([collisionBall direction], velocityChange)];
[ball setDirection:vectorSubtract([ball direction], velocityChange)];
// Animate both balsl the remaining distance following collision
[collisionBall moveDistance:remainder];
[ball moveDistance:remainder];
}
}
}
}
TIMESTEP_AMOUNT is currently defined as 0.1  I figured that was accurate enough.
Any ideas?
change
if (vectorDistance([collisionBall position], [ball position]) < ([collisionBall radius] + [ball radius]))
You need to track back an entire frame before doing the while loop with
[collisionBall moveDistance:TIMESTEP_AMOUNT];
[ball moveDistance:TIMESTEP_AMOUNT];
inside it and then divide the timestep by two and check which side the perfect case is on, then subdivide that and so on,
looping with a variable is a very inefficient way, you can much much higher accuracy with bisection method than that way.
if (vectorDistance([collisionBall position], [ball position]) < ([collisionBall radius] + [ball radius]))
You need to track back an entire frame before doing the while loop with
[collisionBall moveDistance:TIMESTEP_AMOUNT];
[ball moveDistance:TIMESTEP_AMOUNT];
inside it and then divide the timestep by two and check which side the perfect case is on, then subdivide that and so on,
looping with a variable is a very inefficient way, you can much much higher accuracy with bisection method than that way.
Sir, e^iÏ€ + 1 = 0, hence God exists; reply!
Woah, I found this by total coincidence
http://homepage.mac.com/felinegames/game...suals.html
its on KittyMac's homepage, the vortex game I mentioned earler.
http://homepage.mac.com/felinegames/game...suals.html
its on KittyMac's homepage, the vortex game I mentioned earler.
Sir, e^iÏ€ + 1 = 0, hence God exists; reply!
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