C/C++ Int To Char*

Nick

Sage

Posts: 1,066
Joined: 2004.07

Post: #1

Sep 6, 2005 — 08:10 AM

I understand some fundamental problems with this conversion (int == 16 bits, char == 8) but what I need is some way to convert an int into a char*. I have a function that'll print a char* string into OpenGL and I have an int framerate. I would like to somehow use this function to display my framerate over my OpenGL drawings. Any ideas?

TomorrowPlusX

Sage

Posts: 1,199
Joined: 2004.10

Post: #2

Sep 6, 2005 — 08:30 AM

What you need to do is *format* the int into a character buffer.

Try something like:

Code:

const int MAX_SIZE = 255;

char buf[MAX_SIZE];

snprintf( buf, MAX_SIZE, "FPS: %d", myFps );

//now, pass "buf" to your print function

Andrew

Member

Posts: 208
Joined: 2005.04

Post: #3

Sep 6, 2005 — 08:34 AM

sprintf or snprintf... see the man pages

also, on Mac OS X, an int is 32 bits

Nick

Sage

Posts: 1,066
Joined: 2004.07

Post: #4

Sep 6, 2005 — 08:35 AM

Oops on the bit part. I never could remember how many bits went into each different type.

Thanks for the tips. I didn't think of that at all. Hence why I am the beginner and you all are the teachers (though my post count is un-godly huge

Zekaric

Member

Posts: 131
Joined: 2004.10

Post: #5

Sep 12, 2005 — 10:02 AM

Or itoa() and various flavours will do the trick seeing that sprintf does a crap load of other stuff as well.

Code:

int ival = 10

char sval[20];

_itoa(ival, sval, 10);

(Currently on a windows machine so I don't know if the underscore is required.)

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